Problem 85 C , I got 1.84/R, can you please explain how to get 1.44/R

Amany, we can't use a = r x alpha since the cylinder is slipping, so use torque = I alpha. The trick is finding the normal force. T + N = Mg, so N = 0.2 Mg. The Tension is acting in the up direction, causing the clockwise rotation. The friction force acts to the right opposing the rotation caused by the tension. Final equation is TR - friction x R = 1/2 MR^2. This will yield 1.44g/R as the solution.  John

Thank you