Want the latest in our educational opportunities? Sign up for our email list here!
Educators apply here to access accessments. Approval may take one to two days.
On the QP and AM MC #37 shouldn&amp;#x27;t the correct answer be d) 4times wavelength
Rebecca, lambda is equal to h/p. The energy of the electron for 600 V is U = KE = qV = 600q.
Use the relationship p^2/2m = KE. For the same electron, momentum, p, is proportional to the square root of KE.
For V = 150 V, U = KE = qV = 150q, or 1/4th the initial KE
Since momentum is proportional to the square root of the KE, the new momentum is proportional to the square root of 1/4, which is 1/2. Plug 1/2p in the h/p equation and we get a wavelength that is twice the original wavelength.
What to you think?