Outage Notification

#22 There is no answer.  I calculate the enthalpy of combustion for methanol, given the information provided, to be -645 kJ.  
#24 The formation of ammonia is reverse of what is given, so the value should be the negative of the given value (and divide by 2).  The answer should be -2457 kJ/mol.  The key says +2457 kJ/mol

Hi Yoko,
For #22 you are correct the answer is -645 kJ.  Foe #24 you are also correct the answer should be -2457 kJ/mol.  Both these corrections will be made and a new file will be uploaded. Thank you!