## Universal Gravitation Chapter Problems File

```On Universal Gravitation Chapter Problems, check out problem 34b. IT appears that the right answer is 1.69 x 10^7 m, not 2.04 x 10^7 m. Looks like a problem in adding in scientific notation. Could you check that out. BTW, that matches up with Wikipedia's report on the height for a Geosynchronous orbit around Mars. Could you comment and correct.

Steve McNally, Glen Rock High School
```
```Steve,

I got 5082.7 s and corrected this answer.

Thank you.

Yuriy```
```36b is 26455s not 5082.7s
`Alexander, you are correct, and a new version of the problems will be uploaded. I cut it to two significant figures and averaged the value you get when you use Kepler's Law and measurements of the earth's radius and mass to 4 sig figs. The answer now is 2.7 x 10^4 s.  Thanks for the correction, John.`
`New version is now posted.`
```Yurly, referring to question from one month ago, above. The Geostationary orbit for mars is 2.03 E7 m from the center of the planet, but the question was for the height above the surface. Doesn't that mean it should be 2.03 E7 m - 3.39 E6 m (mean radius of Mars) for a height of 1.7 E7 m. Could you check and update the file.